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6÷2[1+2]=?

acheron

TRIBE Member
BEDMAS
Brackets
Exponents
Multiplication or Division (left to right in the problem)
Addition or Subtraction (left to right in the problem)

6/2[1+2]
6/2[3]
3*3
=9
 
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the_fornicator

TRIBE Member
BEDMAS
Brackets
Exponents
Multiplication or Division (left to right in the problem)
Addition or Subtraction (left to right in the problem)

6/2[1+2]
6/2[3]
3*3
=9

If brackets is first, then get rid of the brackets properly and complete the multiplication.

6/2[1+2]
6/2[3] (the two is multiplied into the 3 as there is a 3 in the brackets -this is no different than if there were any other rational value in the brackets)
6/6
=1
 

SneakyPete

TRIBE Member
6/2[3] (the two is multiplied into the 3 as there is a 3 in the brackets -this is no different than if there were any other rational value in the brackets)
Sure the 3 is in the brackets, but the operation is actually outside the brackets. The only reason it's in the bracket is because it is written in short form. It's actually read as 6/2x3.
 
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lobo

TRIBE Member
Sure the 3 is in the brackets, but the operation is actually outside the brackets. The only reason it's in the bracket is because it is written in short form. It's actually read as 6/2x3.
Correct and you're supposed to do multiplication and division from left to right in order. So answer is 9.

Lobo
 
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Klubmasta Will

TRIBE Member
it's a bit of trick question, as people have a tendency to think that, since the multiplication symbol is missing between the 2 and the open bracket, that somehow that operation should occur earlier in the order.

if the question was written "6÷2 x [1+2]=?"everyone would get it right.
 

Bernnie Federko

TRIBE Member
Nine. 6 ÷ 2 x (1+2).
One would be 6 ÷ ( 2 (1+2) ). Only with that extra set of parentheses can you correctly do the multiplication before the division.
 

the_fornicator

TRIBE Member
Sure the 3 is in the brackets, but the operation is actually outside the brackets. The only reason it's in the bracket is because it is written in short form. It's actually read as 6/2x3.
IMO, you're changing the precedence of the equation then. Your substituting brackets with a straight multiplication which is it not.

It's a bracket -not a multiplication.

6/2(3) so you have to put the 2 into the 3 first. That's how you get rid of the brackets.

Edit: Google says 9. I say Google is stupid.
 

Bass-Invader

TRIBE Member
IMO, you're changing the precedence of the equation then. Your substituting brackets with a straight multiplication which is it not.

It's a bracket -not a multiplication.

6/2(3) so you have to put the 2 into the 3 first. That's how you get rid of the brackets.

Edit: Google says 9. I say Google is stupid.
The order refers to doing things in the brackets first, not getting rid of the brackets. It is 9 because there's an implicit multiplication symbol there. I got it wrong my first try too.
 
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