Hi Guest:
Welcome to TRIBE, the online home of TRIBE MAGAZINE. If you'd like to post here, or reply to existing posts on TRIBE, you first have to register. Join us!

If brackets is first, then get rid of the brackets properly and complete the multiplication.

6/2[1+2]
6/2[3] (the two is multiplied into the 3 as there is a 3 in the brackets -this is no different than if there were any other rational value in the brackets)
6/6
=1

6/2[3] (the two is multiplied into the 3 as there is a 3 in the brackets -this is no different than if there were any other rational value in the brackets)

Sure the 3 is in the brackets, but the operation is actually outside the brackets. The only reason it's in the bracket is because it is written in short form. It's actually read as 6/2x3.

Sure the 3 is in the brackets, but the operation is actually outside the brackets. The only reason it's in the bracket is because it is written in short form. It's actually read as 6/2x3.

it's a bit of trick question, as people have a tendency to think that, since the multiplication symbol is missing between the 2 and the open bracket, that somehow that operation should occur earlier in the order.

if the question was written "6÷2 x [1+2]=?"everyone would get it right.

Nine. 6 ÷ 2 x (1+2).
One would be 6 ÷ ( 2 (1+2) ). Only with that extra set of parentheses can you correctly do the multiplication before the division.

Sure the 3 is in the brackets, but the operation is actually outside the brackets. The only reason it's in the bracket is because it is written in short form. It's actually read as 6/2x3.

The order refers to doing things in the brackets first, not getting rid of the brackets. It is 9 because there's an implicit multiplication symbol there. I got it wrong my first try too.