# 6÷2[1+2]=?

9 or 1?

=1

+1

#### acheron

##### TRIBE Member
BEDMAS
Brackets
Exponents
Multiplication or Division (left to right in the problem)
Addition or Subtraction (left to right in the problem)

6/2[1+2]
6/2
3*3
=9

9 is correct

#### the_fornicator

##### TRIBE Member
BEDMAS
Brackets
Exponents
Multiplication or Division (left to right in the problem)
Addition or Subtraction (left to right in the problem)

6/2[1+2]
6/2
3*3
=9

If brackets is first, then get rid of the brackets properly and complete the multiplication.

6/2[1+2]
6/2 (the two is multiplied into the 3 as there is a 3 in the brackets -this is no different than if there were any other rational value in the brackets)
6/6
=1

#### Wiseman

##### TRIBE Member
exactly. This could be represented as:

6
______
2(1+2)

#### Re: Shoe

##### TRIBE Member
exactly. This could be represented as:

6
______
2(1+2)
No it can't, because then it would've had to have been written as 6÷(2[1+2])=?

#### SneakyPete

##### TRIBE Member
6/2 (the two is multiplied into the 3 as there is a 3 in the brackets -this is no different than if there were any other rational value in the brackets)
Sure the 3 is in the brackets, but the operation is actually outside the brackets. The only reason it's in the bracket is because it is written in short form. It's actually read as 6/2x3.

#### lobo

##### TRIBE Member
Sure the 3 is in the brackets, but the operation is actually outside the brackets. The only reason it's in the bracket is because it is written in short form. It's actually read as 6/2x3.
Correct and you're supposed to do multiplication and division from left to right in order. So answer is 9.

Lobo

#### Krzysiu

##### TRIBE Member #### Polymorph

##### TRIBE Member
6 divided by 2 = 3
1+2 = 3
multiplied =
9

(but if it was added it would be 6)

9

qed

#### Klubmasta Will

##### TRIBE Member
it's a bit of trick question, as people have a tendency to think that, since the multiplication symbol is missing between the 2 and the open bracket, that somehow that operation should occur earlier in the order.

if the question was written "6÷2 x [1+2]=?"everyone would get it right.

#### Bernnie Federko

##### TRIBE Member
Nine. 6 ÷ 2 x (1+2).
One would be 6 ÷ ( 2 (1+2) ). Only with that extra set of parentheses can you correctly do the multiplication before the division.

#### the_fornicator

##### TRIBE Member
Sure the 3 is in the brackets, but the operation is actually outside the brackets. The only reason it's in the bracket is because it is written in short form. It's actually read as 6/2x3.
IMO, you're changing the precedence of the equation then. Your substituting brackets with a straight multiplication which is it not.

It's a bracket -not a multiplication.

6/2(3) so you have to put the 2 into the 3 first. That's how you get rid of the brackets.

#### Bernnie Federko

##### TRIBE Member
Left to Right. Order of Operations. BEDMAS

##### TRIBE Member
IMO, you're changing the precedence of the equation then. Your substituting brackets with a straight multiplication which is it not.

It's a bracket -not a multiplication.

6/2(3) so you have to put the 2 into the 3 first. That's how you get rid of the brackets.